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8p^2-20p=0
a = 8; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·8·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*8}=\frac{0}{16} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*8}=\frac{40}{16} =2+1/2 $
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